Soi c\u1ea7u x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00e0 \u0111\u1ec3 t\u00ecm ra c\u1eb7p l\u00f4 \u0111\u1eb9p nh\u1ea5t ch\u00ednh x\u00e1c nh\u1ea5t \u0111\u1ec3 \u0111\u00e1nh trong ng\u00e0y v\u00e0 d\u00e0nh \u0111\u01b0\u1ee3c chi\u1ebfn th\u1eafng. C\u00f3 r\u1ea5t nhi\u1ec1u c\u00e1c ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 kh\u00e1c nhau \u0111\u01b0\u1ee3c chia s\u1ebb tr\u00ean internet. Th\u1ebf nh\u01b0ng kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng ph\u00e1p n\u00e0o c\u00f9ng ch\u00ednh x\u00e1c, c\u0169ng mang \u0111\u1ebfn chi\u1ebfn th\u1eafng cho ng\u01b0\u1eddi soi c\u1ea7u. \u1ede b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y, m\u00ecnh s\u1ebd h\u01b0\u1edbng d\u1eabn c\u00e1c b\u1ea1n c\u00e1ch soi c\u1ea7u XSMB theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7<\/strong>. Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 MB n\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c m\u00ecnh \u00e1p d\u1ee5ng trong nh\u1eefng b\u00e0i soi c\u1ea7u l\u00f4 v\u00e0 d\u1ef1 \u0111o\u00e1n XSMB h\u00e0ng ng\u00e0y. Hy v\u1ecdng s\u1ebd gi\u00fap cho c\u00e1c b\u1ea1n c\u00f3 \u0111\u01b0\u1ee3c cho m\u00ecnh nh\u1eefng kinh nghi\u1ec7m v\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c nh\u1ea5t.<\/p>\n Soi c\u1ea7u l\u00f4 MB<\/strong> l\u00e0 m\u1ed9t s\u1ef1 tr\u00f9ng h\u1ee3p trong c\u00e1ch soi c\u1ea7u k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m tr\u01b0\u1edbc v\u00e0 k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m nay. Theo ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u n\u00e0y th\u00ec c\u00e1c b\u1ea1n c\u1ea7n ph\u1ea3i \u0111\u00e1nh 2 c\u1eb7p l\u00f4 trong 3 ng\u00e0y, khi n\u00e0o tr\u00fang th\u00ec chuy\u1ec3n sang \u0111\u00e1nh con kh\u00e1c. C\u00e1c b\u1ea1n c\u1ea7n ph\u1ea3i chu\u1ea9n b\u1ecb m\u1ed9t s\u1ed1 v\u1ed1n kh\u00e1 l\u1edbn \u0111\u1ec3 theo ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc n\u00e0y. \u0110i\u1ec3m n\u1ed5i b\u1eadt c\u1ee7a ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u x\u1ed5 s\u1ed1 MB n\u00e0y l\u00e0 n\u00f3 c\u00f3 t\u00ednh an to\u00e0n cao. Mang l\u1ea1i t\u00e2m l\u00fd tho\u1ea3i m\u00e1i v\u00e0 ch\u00ednh x\u00e1c nh\u1ea5t cho ng\u01b0\u1eddi soi c\u1ea7u x\u1ed5 s\u1ed1.<\/p>\n Soi c\u1ea7u XSMB theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7 c\u00e1c b\u1ea1n c\u1ea7n l\u00e0m theo c\u00e1c b\u01b0\u1edbc sau:<\/p>\n B\u01b0\u1edbc 1:<\/strong> B\u1ea1n l\u1ea5y t\u1ed5ng s\u1ed1 \u0111\u1ea7u v\u00e0 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y h\u00f4m nay. N\u1ebfu t\u1ed5ng \u0111\u00f3 l\u1edbn h\u01a1n 10 th\u00ec ta c\u1ed9ng ti\u1ebfp t\u1eebng s\u1ed1 trong t\u1ed5ng \u0111\u00f3. C\u00f2n n\u1ebfu t\u1ed5ng \u0111\u00f3 b\u1eb1ng 10 th\u00ec ra l\u1ea5y b\u1eb1ng 0. N\u1ebfu nh\u1ecf h\u01a1n 10 th\u00ec ch\u00fang ta l\u1ea5y lu\u00f4n t\u1ed5ng \u0111\u00f3.<\/p>\n V\u00ed d\u1ee5:<\/span><\/em><\/strong> Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 MB ng\u00e0y 1-10-2024 l\u00e0: 19515<\/strong> (1 l\u00e0 s\u1ed1 \u0111\u1ea7u v\u00e0 5 l\u00e0 s\u1ed1 cu\u1ed1i)<\/p>\n Ta l\u1ea5y t\u1ed5ng = 1 + 5 = 6. Nh\u01b0 v\u1eady ch\u00fang ta \u0111\u01b0\u1ee3c t\u1ed5ng b\u1eb1ng 6.<\/p>\n (N\u1ebfu t\u1ed5ng > 10 th\u00ec ta s\u1ebd c\u1ed9ng t\u1eebng s\u1ed1 trong t\u1ed5ng \u0111\u00f3. V\u00ed d\u1ee5 t\u1ed5ng = 11 > 10, ta s\u1ebd ti\u1ebfp t\u1ee5c l\u1ea5y 1 + 1 = 2 => T\u1ed5ng = 2)<\/p>\n B\u01b0\u1edbc 2:<\/strong> L\u1ea5y b\u00f3ng d\u01b0\u01a1ng c\u1ee7a t\u1ed5ng \u0111\u00f3 ta \u0111\u01b0\u1ee3c m\u1ed9t s\u1ed1 g\u1ecdi l\u00e0 X.<\/p>\n V\u00ed d\u1ee5:<\/span><\/em><\/strong> Nh\u01b0 t\u1ed5ng \u1edf tr\u00ean b\u1eb1ng 6 th\u00ec b\u00f3ng c\u1ee7a 6 l\u00e0 1. V\u1eady X = 1.<\/p>\n B\u01b0\u1edbc 3:<\/strong> Ta th\u1ed1ng k\u00ea gi\u1ea3i 7 trong k\u1ebft qu\u1ea3 XSMB. Ta s\u1ebd c\u00f3 4 gi\u1ea3i 7 v\u00e0 m\u1ed7i gi\u1ea3i 7 c\u00f3 2 ch\u1eef s\u1ed1 n\u00ean ta s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c 8 ch\u1eef s\u1ed1.<\/p>\n Ti\u1ebfp theo ch\u1ecdn 2 s\u1ed1 xu\u1ea5t hi\u1ec7n nhi\u1ec1u nh\u1ea5t trong 8 s\u1ed1 \u0111\u00f3. N\u1ebfu nhi\u1ec1u s\u1ed1 xu\u1ea5t hi\u1ec7n b\u1eb1ng nhau ta \u01b0u ti\u00ean s\u1ed1 xu\u1ea5t hi\u1ec7n tr\u01b0\u1edbc t\u1eeb tr\u00e1i qua ph\u1ea3i theo k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. Ta \u0111\u01b0\u1ee3c 2 s\u1ed1 l\u00e0 A,B.<\/p>\n V\u00ed d\u1ee5:<\/span><\/em><\/strong> Gi\u1ea3i 7 c\u1ee7a ng\u00e0y 1\/10\/2024 l\u00e0 78 45 16 07<\/strong>. Ta th\u1ea5y s\u1ed1 7 xu\u1ea5t hi\u1ec7n 2 l\u1ea7n. C\u00f2n c\u00e1c s\u1ed1 c\u00f2n l\u1ea1i l\u00e0 1 l\u1ea7n.<\/p>\n Sau khi xem x\u00e9t ta l\u1ef1a ch\u1ecdn s\u1ed1 7 v\u00e0 s\u1ed1 8.<\/p>\n B\u01b0\u1edbc 4:<\/strong> Ta gh\u00e9p X \u0111\u00e3 t\u00ecm \u0111\u01b0\u1ee3c \u1edf b\u01b0\u1edbc 2 v\u1edbi hai s\u1ed1 t\u00ecm \u0111\u01b0\u1ee3c \u1edf b\u01b0\u1edbc 3. Ta s\u1ebd \u0111\u01b0\u1ee3c 2 l\u00f4 l\u00e0 XA v\u00e0 XB.<\/p>\n V\u00ed d\u1ee5:<\/span><\/em><\/strong> Theo nh\u01b0 c\u00e1c b\u01b0\u1edbc \u1edf tr\u00ean l\u00e0 c\u00f3 X = 1. Gh\u00e9p v\u1edbi hai s\u1ed1 \u1edf b\u01b0\u1edbc 3 l\u00e0 7 v\u00e0 8 t\u00ecm \u0111\u01b0\u1ee3c \u1edf tr\u00ean. Ta s\u1ebd c\u00f3 2 c\u1eb7p l\u00f4 l\u00e0 17 \u2013 18.<\/p>\n B\u01b0\u1edbc 5:<\/strong> \u0110\u00e1nh 2 c\u1eb7p l\u00f4 t\u00ecm \u0111\u01b0\u1ee3c trong 3 ng\u00e0y v\u1edbi t\u1ef7 l\u1ec7 1:3:10 (ng\u00e0y 1 \u0111\u00e1nh 10 \u0111i\u1ec3m m\u1ed9t con kh\u00f4ng tr\u00fang th\u00ec ng\u00e0y 2 \u0111\u00e1nh 30 \u0111i\u1ec3m m\u1ed9t con, ng\u00e0y cu\u1ed1i 3 \u0111\u00e1nh 100 \u0111i\u1ec3m 1 con). N\u1ebfu tr\u00fang th\u00ec b\u1ecf hai c\u1eb7p \u0111\u00f3 t\u00ecm hai c\u1eb7p kh\u00e1c \u0111\u1ec3 \u0111\u00e1nh. N\u1ebfu 3 ng\u00e0y kh\u00f4ng v\u1ec1 th\u00ec b\u1ecf, nu\u00f4i ti\u1ebfp 3 ng\u00e0y kh\u00e1c. N\u1ebfu \u0111\u00e1nh 1 tu\u1ea7n m\u00e0 c\u00f3 l\u00e3i th\u00ec ngh\u1ec9 1 tu\u1ea7n r\u1ed3i \u0111\u00e1nh ti\u1ebfp. C\u00f2n kh\u00f4ng c\u00f3 l\u00e3i th\u00ec \u0111\u00e1nh ti\u1ebfp tu\u1ea7n ti\u1ebfp theo c\u00f3 l\u00e3i r\u1ed3i ngh\u1ec9 1 tu\u1ea7n.<\/p>\n Tr\u00ean \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u XSMB theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7<\/strong> ch\u00ednh x\u00e1c nh\u1ea5t hi\u1ec7n nay. Kh\u00f4ng mang ch\u1ec9 mang l\u1ea1i l\u1ee3i nhu\u1eadn r\u1ea5t cao m\u00e0 n\u00f3 c\u00f2n \u0111\u1ea3m b\u1ea3o an to\u00e0n cho ng\u01b0\u1eddi ch\u01a1i. Hy v\u1ecdng v\u1edbi ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u x\u1ed5 s\u1ed1 MB n\u00e0y. S\u1ebd gi\u00fap c\u00e1c b\u1ea1n lu\u00f4n d\u00e0nh \u0111\u01b0\u1ee3c chi\u1ebfn th\u1eafng khi tham gia tr\u00f2 ch\u01a1i l\u00f4 \u0111\u1ec1 online.<\/p>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n
<\/h2>\n
H\u01b0\u1edbng d\u1eabn soi c\u1ea7u XSMB theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7<\/h2>\n
chuy\u00ean gia b\u1eaft s\u1ed1 c\u1ea7u mi\u1ec1n b\u1eafc si\u00eau chu\u1ea9n<\/span><\/h4>\n
\nC\u00e1ch soi c\u1ea7u XSMB theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7<\/span><\/h1>\n<\/div>\n
C\u00e1ch soi c\u1ea7u XSMB theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7<\/span><\/h1>\n<\/div>\n\n
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